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A ball of mass m moving at a speed v col...

A ball of mass `m` moving at a speed `v` collides with another ball of mass `3m` at rest. The lighter block comes to rest after collisoin. The coefficient of restitution is

A

(a) `1/2`

B

(b) `2/3`

C

(c) `1/4`

D

(d) None of these

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The correct Answer is:
To solve the problem, we need to find the coefficient of restitution for the collision between a ball of mass `m` moving at speed `v` and another ball of mass `3m` at rest. After the collision, the lighter ball comes to rest. ### Step-by-Step Solution: 1. **Identify the Initial Conditions:** - Mass of the first ball (lighter ball) = `m` - Initial velocity of the first ball = `v` - Mass of the second ball (heavier ball) = `3m` - Initial velocity of the second ball = `0` (at rest) 2. **Determine the Final Conditions:** - After the collision, the lighter ball comes to rest, so its final velocity = `0`. - Let the final velocity of the heavier ball be `v'`. 3. **Apply the Conservation of Linear Momentum:** - According to the law of conservation of momentum: \[ \text{Initial Momentum} = \text{Final Momentum} \] - Initial momentum = \( m \cdot v + 3m \cdot 0 = mv \) - Final momentum = \( m \cdot 0 + 3m \cdot v' = 3mv' \) - Setting the initial momentum equal to the final momentum: \[ mv = 3mv' \] - Dividing both sides by `m` (assuming `m` is not zero): \[ v = 3v' \] - Therefore, we can express the final velocity of the heavier ball as: \[ v' = \frac{v}{3} \] 4. **Calculate the Coefficient of Restitution (e):** - The coefficient of restitution is defined as: \[ e = \frac{\text{Velocity of separation}}{\text{Velocity of approach}} \] - The velocity of approach (before collision) is the relative speed of the lighter ball towards the heavier ball: \[ \text{Velocity of approach} = v - 0 = v \] - The velocity of separation (after collision) is the relative speed of the heavier ball moving away from the lighter ball: \[ \text{Velocity of separation} = v' - 0 = v' = \frac{v}{3} \] - Substituting these values into the coefficient of restitution formula: \[ e = \frac{\frac{v}{3}}{v} = \frac{1}{3} \] 5. **Final Answer:** - The coefficient of restitution \( e \) is \( \frac{1}{3} \).

To solve the problem, we need to find the coefficient of restitution for the collision between a ball of mass `m` moving at speed `v` and another ball of mass `3m` at rest. After the collision, the lighter ball comes to rest. ### Step-by-Step Solution: 1. **Identify the Initial Conditions:** - Mass of the first ball (lighter ball) = `m` - Initial velocity of the first ball = `v` - Mass of the second ball (heavier ball) = `3m` ...
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