Two identical vehicles are moving with same velocity `v` towards an intersection as shown in figure. If the collision is completely inelastic, then

Options

A. (a) the velocity of separation is zero
B. (b) the velocity of approach is `2vsi n(theta)/(2)`
C. (c) the common velocity after collision is `vco stheta/2`
D. (d) All of the above

Answer

D

Explanation

From the figure we can see that velocity of approach is `2vsi ntheta/2`.
`e=(RVOS)/(RVOA)`
For completely inelastic collision, `e=0`
`:. RVOS=0`
`p_i=p_f`
`:. m[vco stheta/2hati-vsi ntheta/2hatj]+m[co stheta/2hati+vsi ntheta/2hatj]`
`=2mv_c`
`:.` Common velocity `v_c=(vco stheta/2)hati`