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Three identical particles with velocitie...

Three identical particles with velocities `v_0hati`, `-3v_0hatj` and `5v_0hatk` collide successively with each other in such a way that they form a single particle. The velocity vector of resultant particle is

A

(a) `v_0/3(hati+hatj+hatk)`

B

(b) `v_0/3(hati-hatj+hatk)`

C

(c) `v_0/3(hati-3hatj+hatk)`

D

(d) `v_0/3(hati-3hatj+5hatk)`

Text Solution

Verified by Experts

The correct Answer is:
D

`p_1=p_f`
`:.m(v_0hati)+m(-3v_0hatj)+m(5v_0hatk)`
`=3mv`
`:. v=(v_0)/(3)(hati-3hatj+5hatk)`
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DC PANDEY-CENTRE OF MASS, LINEAR MOMENTUM AND COLLISION-Level 1 Objective
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