A man of mass `m` climbs to a rope ladder suspended below a balloon of mass `M`. The balloon is stationary with respect to the ground.
(a) If the man begins to climb the ladder at speed `v` (with respect to the ladder), in what direction and with what speed (with respect to the ground) will the balloon move?
(b) What is the state of the motion after the man stops climbing?

Answer

A, B, C, D

Explanation

Since the system (or COM) was initially at rest. So it will always remain at rest. Because the net external forces are not changing.

(a) `Mv^'=m(v-v^')`
`:. v^'=(mv)/(M+m)`
(b) If man stops climbing, then balloon will also stop to keep the system at rest.