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A man is standing on a cart of mass doub...

A man is standing on a cart of mass double the mass of man. Initially cart is at rest. Now, man jumps horizontally with velocity `u` relative to cart. Then work done by man during the process of jumping will be

A

`(mu^2)/(2)`

B

`(3mu^2)/(4)`

C

`mu^2`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D

`2mv=m(u-v)`

`:. v=u/3`
`:. u-v=(2u)/(3)`
`KE=1/2xxm((2u)/(3))^2+1/2(2m)(u/3)^2`
`=1/3mu^2`
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