A particle of mass `m_0`, travelling at speed `v_0`. Strikes a stationary particle of mass `2m_0`. As a result of the particle of mass `m_0` is deflected through `45^@` and has a final speed of `v_0/sqrt2`. Then the speed of the particle of mass `2m_0` after this collision is

Options

A. (a) `v_0/2`
B. (b) `(v_0)/(2sqrt2)`
C. (c) `sqrt2v_0`
D. (d) `(v_0)/(sqrt2)`

Answer

B

Explanation

`p_i=p_f`
`:. (m_0v_0hati)=m_0v_0/sqrt2(1/sqrt2hati+1/sqrt2hatj)+2m_0v`
`:. v=v_0/4hati-v_0/4hatj`
`:. |v|=sqrt2v_0/4=(v_0)/(2sqrt2)`