(a) A wire `4 m ` long and 0.3 mm, calculate the potential energy stored in the wire. Young's modulus for the material of wire is `2.0xx10^(11) N//m^(2) `.
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A, B, D
(a ) Energy stored `U =1/2` (stress) (strain) (volume ) or `U =1/2(F/A)(Deltal)/(l)(Al)` ` =1/2F.Deltal` `=1/2(100)(0.3xx10^(-3))` `=0.015 J` (b) Work done = Potential energy stored `(1)/(2)k(Deltal)^(2)` `=(1)/(2)((Y_A)/(l))(Deltal)^(2) ("as" k=(YA)/(l))` Substituting the values, we have `W=(1)/(2)((2.0xx10^(11))(10^(-6)))/((2)) (0.1xx10^(-3))^(2)` `=5.0xx10^(-4)J`
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