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What is the density of lead under a pres...

What is the density of lead under a pressure of `2xx10^(8)Nm^(-2)` , if the bulk modulus of lead is `8xx10^(9)Nm^(-2)` and initially the density of lead is `11.4 g cm^(-3)` ?

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
The changed density ,`rho' = (rho)/(1-(dp)/(B))` substituting the values, We have
`rho' = (11.4)/(1-(2.0xx10^(8))/(8.0xx10^(9))` or `rho' = 11.69 g//cm^(3)`
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Knowledge Check

  • A solid block of silver with density 10.5 xx 10^(3) kg m^(-3) is subjected to an external pressure of 10^(7) Nm^(-2) . If the bulk modulus of silver is 17 xx 10^(10) Nm^(-2) . Then the change in density of silver (in kg m^(-3) ) is

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