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Calculate the apprroximate change in den...

Calculate the apprroximate change in density of water in a lake at a depth of `400 m ` below the surface. The density of water at the surface id `1030 kg//m^(3)` and bulk modulus of water is `2xx10^(9) N//m^(2)`.

Text Solution

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The correct Answer is:
B, C
` rho' = (rho)/(1-d_(p)/B)~~rho(1+d_(p)/B)`
`:. Deltarho = rho'-rho = (rho(dp))/B`
`=(rho(rhogh))/B`
`= ((1030)^(2)xx9.8xx400)/(2xx10^(9))`
` = 2.0 kg//m^(3)`
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