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A body of mass M is attached to the lowe...

A body of mass `M` is attached to the lower end of a metal wire, whose upper end is fixed . The elongation of the wire is `l`.

A

Loss in gravitational potential energy of` M` is `Mgl`

B

The elastic potential energy stored in the wire is ` Mgl`

C

The elastic potential energy stored in the wire is `1/2 Mgl`

D

Heat produced is `1/2 Mgl`

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
Half of energy is lost in heat and rest half is stored as elastic potential energy .
` l = (Mgl)/(AY)` …(i)
` U = 1/2 Kl^(2) = 1/2((YA)/(L))l^(2)` …(ii)
From Eqs. (i) and (ii) , we can prove that
`U = 1/2 Mgl`
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