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A light rod of length of length 2 m is ...

A light rod of length of length `2 m` is suspended from a ceiling horizontally by means of two vertical wires of equal length tied to its ends. One of the wires is made of steel and is of cross - section `10^(-3) m^(2)` and the other is of brass of cross- section `2xx10^(-3) m^(2).x` is the distance from the steel wire end, at which a weight may be hung. ` Y_(steel) = 2xx10^(11) Pa and Y_(brass) = 10^(11) Pa`
Which of the following statement(s) is /are correct ?

A

`x= 1.2 m` , if the strains of both the wires are to be equal

B

` x= 1.42 m` , if the stresses of the wires are to be equal

C

`x= 1m` , if the stains of both the wires are to be equal

D

` x = 1.33 m`, if the stresses of the wires are to be equal

Text Solution

Verified by Experts

If stress in steel = stress in brass,
then `(T_(s))/(A_(S)) = (T_(B))/(A_(B))`
`(T_(S))/(T_(B)) = (A_(S))/(A_(B)) = (10^(-3))/(2xx10^(-3)) = 1/2` ...(i)
System is in equilibrium n. So, taking moments about `P`
` T_(S)'x = T_(B)(2-x) rArr (T_(S))/(T_(B)) = (2-x)/x` ...(ii)
If strain in steel = strain in brass ,
then ` (T_(S)//A_(S))/Y_(S) = (T_(B)//A_(B))/Y_(B) = ((10^(-3)) ( 2xx10^(11)))/((2xx10^(-3))(10^(11))) = 1` ...(iii)
From Eqs. (ii) and (iii) , we get `x= 1 m `
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