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A stretched wire is oscillating in third...

A stretched wire is oscillating in third overtone mode. Equation of transverse stationary wave produced in this wire is
`y= A sin (6pix)sin(20pit)`
Here, x is in metres. Find the length of the wire.

Text Solution

Verified by Experts

The correct Answer is:
B, C
From the given equation we can see that
`k=6pim^(-1)`
` lambda= (2pi)/k = (2pi)/(6pi)`
= 1/3m
Now, third overtone mode means four loops as shown below

One loop size is `lambda/2`, therefore total length of wire,
`l=4(lambda/2) = 2lambda`
`=2(1/3) m`
` = 2/3m `
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