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Two different stretched wires have same ...

Two different stretched wires have same tension and mass per unit length. Fifth overtone frequency of the first wire is equal to second harmonic frequency of the second wire. Find the ratio of their lengths.

Text Solution

Verified by Experts

The correct Answer is:
3
`6[(T//mu)/(2l_1)] = 2[(T//mu)/(2l_2)]`
`:. l_(1)/l_(2) = 3 ` .
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