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When tension of a string is increased by...

When tension of a string is increased by 2.5 N, the initial frequency is altered in the ratio of 3:2. The initial tension in the string is

A

6N

B

5N

C

4N

D

2N

Text Solution

Verified by Experts

The correct Answer is:
D
`:. f prop sqrtT`
`:. f_1/f_2 = sqrt(T_1/T_2)`
`:. 3/2 = sqrt((T+2.5)/T)`
Solving, we get `T = 2N`.
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Knowledge Check

  • The tension in the string is:

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    29.4 N
    B
    39.2 N
    C
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    D
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  • In the previous question, the tension in the string is:

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    B
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    C
    `(50)/(8) N`
    D
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