Home
Class 11
PHYSICS
Among two interfering sources, let S1 be...

Among two interfering sources, let `S_1` be ahead of the phase by `90^@` relative to `S_2` . If an observation point P is such that `PS_1 - PS_2 = 1.5 lambda` , the phase difference between the waves from `S_1 and S_2` reaching P is

A

`3pi`

B

`(5pi)/2`

C

`(7pi)/2`

D

`4pi`

Text Solution

Verified by Experts

The correct Answer is:
B

`Delta phi_1 = pi/2`
`Delta phi_2 = ((2pi)/lambda) (Deltax)`
`= ((2pi)/lambda) (1.5 lambda)`
` = 3pi `
`:. Delta phi_("net") = Delta phi_2 - Delta phi_1 = (5pi)/2` .
Promotional Banner

Topper's Solved these Questions

  • SUPERPOSITION OF WAVES

    DC PANDEY|Exercise Level 2 More Than One Correct|6 Videos
  • SUPERPOSITION OF WAVES

    DC PANDEY|Exercise More than One correct Options|1 Videos
  • SUPERPOSITION OF WAVES

    DC PANDEY|Exercise Subjective Questions|6 Videos
  • SOUND WAVES

    DC PANDEY|Exercise Exercise 19.7|4 Videos
  • THERMOMETRY THERMAL EXPANSION AND KINETIC THEORY OF GASES

    DC PANDEY|Exercise Medical entrance gallary|30 Videos

Similar Questions

Explore conceptually related problems

Among two interfering sources, let A be ahead in phase by 54^(@) relative to B . If the observations be taken from point P , such that PB - PA = 1.5 lambda , deduce the phase difference between the waves from A and B reaching P .

Among the two interfering monochromatic sources A and B, A is ahead of B in phase by 66^@ . If the observation be taken from point P, such that PB-PA=lambda//4 . Then the phase difference between the waves from A and B reaching P is

A coherent light is incident on two paralle slits S_(1) and S_(2) . At a point P_(1) the frings will be dark if the phase difference between the rays coming from S_(1) and S_(2) is

Three coherent sources S_(1), S_(2)" and" S_(3) can throw light on a screen. With S_(1) switched on intensity at a point P on the screen was observed to be I. With only S_(2) on, intensity at P was 2I and when all three are switched on the intensity at P becomes zero. Intensity at P is I when S_(1)" and" S_(2) are kept on. Find the phase difference between the waves reaching at P from sources S_(1) "and" S_(3) .

Two waves of equal amplitude a from two coherent sources (S_1 & S_2) interfere at a point R such that S_2R-S_1R =1.5 lambda The intensity at point R Would be

Sounds from two identical sources S_(1) and S_(2) reach a point P . When the sounds reach directly, and in the same phase, the intensity at P is I_(0) . The power of S_(1) is now reduced by 64% and the phase difference between S_(1) and S_(2) is varied continuously. The maximum and minimum intensities recorded at P are now I_("max") and I_("min")

In experimental set up of interference the twol interfering sources S_(1) and S_(2) have an initial phase difference corresponding to a path difference of lambda//4 . The phase difference due to path difference between the twoll interfering waves at a point of constructive and destructive interference respectively is