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Incident wave y= A sin (ax + bt+ pi/2) i...

Incident wave `y= A sin (ax + bt+ pi/2)` is reflected by an obstacle at x = 0 which reduces intensity of reflected wave by 36%. Due to superposition, the resulting wave consists of a standing wave and a travelling wave given by
`y= -1.6 sin ax sin bt + cA cos (bt + ax)`
where A, a, b and c are positive constants.
2. Value of c is

A

0.2

B

0.4

C

0.6

D

0.3

Text Solution

Verified by Experts

The correct Answer is:
A
`y = y_i + y_r `
` = A sin (ax + bt + pi//2)`
`+0.8 A sin (ax - bt +pi//2)`
` = [0.8 A sin (ax +bt + pi/2)`
`+ 0.8 A sin (ax -bt + pi/2)] `
`+ 0.2 A sin (ax + bt+ pi/2)`
`= 1.6 sin ax sin bt + 0.2 A cos (bt + ax)`
`:. c = 0.2`
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