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A string fixed at both ends is vibrating...

A string fixed at both ends is vibrating in the lowest mode of vibration for which a point at quarter of its length from one end is a point of maximum vibration . The note emitted has a frequency of `100 Hz`. What will be the frequency emitted when it vibrates in the next mode such that this point is again a point of maximum vibratin ?

Text Solution

Verified by Experts

The correct Answer is:
C
`L/4 = lambda/4`
`:. L = lambda`

In the next higher mode, there will be total 6 loops
and the desired frequency is
`(6/2)(100) = 300 Hz. `
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