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At a given temperature, rotational kinet...

At a given temperature, rotational kinetic energy of diatomic gas is `K_(0)`. Find its translational and total kinetic energy.

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The correct Answer is:
B, C

`(f_T)/(f_R) = 3/2 = (K_T)/(K_R) = (K_T)/(K_O)`
:. `K_T = 3/2 K_O`.
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