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4 g hydrogen is mixed with 11.2 litre of...

`4 g` hydrogen is mixed with 11.2 litre of He at (STP) in a container of volume 20 litre. If the final temperature is `300 K`, find the pressure.

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The correct Answer is:
A, B, C
`4 g "hydrogen" = 2 "moles hydrogen"`
11.2 litre He at (STP) `= 1/2` mole of (He)
`p = p_H + p_(He) = (n_H + n_(He)) (RT)/(V)`
= `(2+1/2) (8.31 xx (300 K))/((20 xx 10^-3)m^3)`
=`3.12 xx 10^5 N//m^2`.
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