Two gases occupy two containers (A) and (B). The gas in (A) of volume `0.11 m^3` experts a pressure of `1.38 Mpa`. The gas in (B) of volume `0.16 m^3` experts a pressure of `0.69 Mpa. Two containers are united by a tube of negligible volume and the gases are allowed to intermingle. What is the final pressure in the container if the temperature remains constant ?

Answer

A

Explanation

`n = n_1 + n_2`
`(p V)/(R T) = (p_1 V_1)/(R T) + (P_2 V_2)/( R T)`
`:. p = (p_1 V_1 + p_2 V_2)/(V)`
= `((0.11)(1.38) + (0.16)(0.69))/(0.11 +0.16)`
= `0.97 Mpa`.