Temperature of diatomic gas is `300 K`. If moment of intertia of its molecules is `8.28 xx 10^-38 g- cm^2`. Calculate their root mean square angular velocity.

Answer

A, C, D

Explanation

In diatomic gas rotational degree of freedom is two.
:. `Rotational (KE) of one molecule
`1/2 I omega^2 = f/2 k T = k T`
`:. omega = sqrt((2 k T)/(I))`
= `sqrt((2 xx 1.38 xx 10^-23 xx 300)/(8.28 xx 10^-38 xx 10^-9))`
= `10^13 "rad" //s`.