The pressure of a gas in a `100 mL` container is `200 kPa` and the. Average translational kinetic energy of each gas particle is `6 xx 10^-21 J`. Find the number of gas particles in the container. How many moles are there in the container ?

Answer

A, B, C

Explanation

`K = 3/2 k T rArr T =(2 K)/(3 K)`
Now, `n = (p V)(R T) = (3 k p V)/(2 K R)`
= `(3 (200 xx 10^3)(0.1 xx 10^-3)(1.38 xx 10^-23))/(2 xx 6 xx 10^-21 xx 8.31)`
= `8.3 xx 10^-3 mol`
Now, `N = nN_A`
= `(8.3 xx 10^3)(6.02 xx 10^23)`
= `5 xx 10^21`.