A `2.00 mL` volume container contains `50 mg` of gas at a pressure of `100 kPa`. The mass of each gas particle is `8.0 xx 10^-26 kg`. Find the average translational kinetic energy of each particle

Answer

A, B, D

Explanation

`K_T = 3/2 k T= 3/2 k((p V)/(n R))`
=`3/2 k (p V)/((M//N_A)R)`
= `(3 k P V m N_A)/(2 M R)`
`(3 xx 1.38 xx10^-23) (100 xx 10^3)`
= `((2 xx 10^-6)(8.0 xx 10^-23)(6.02 xx 10^23))/(2 xx (50 xx 10^-3)(8.31))`
= `4.8 xx 10^-22 J`.