Call the (rms) speed of the molecules in an ideal gas `V_(0)` at temperature `T_(0)` and pressure `p_(0)`. Find the speed if (a) the temperature id raised from `T_0 = 293 K "to" 573 K` (b) the pressure is doubled and `T = T_0` ( c) the molecular weight of each of the gas molecules is tripled.

Answer

A, B, C, D

Explanation

(a) `v_( r m s) prop sqrt(T)`
`:. V_0 = (sqrt((T')/(T))) v_0 = (sqrt((573)/(293)))v_0`
= `1.40 v_0`
(b) `v_(r m s)` does not depend on pressure, as long as temperature remains constant.
(c ) `v_(r m s) = sqrt((3 R T)/(M)) "or" v_(r m s) prop (1)/ sqrt((M))`.