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A gas is found to be obeyed the law p^2V...

A gas is found to be obeyed the law `p^2V = constant`. The initial temperature and volume are `T_0 and V_0`. If the gas expands to a volume `3 V_0`, then the final temperature becomes.

A

`sqrt (3) T_0`

B

`sqrt (2) T_0`.

C

`(T_0)/(sqrt (3)`.

D

`(T_(0))/(sqrt(2))`.

Text Solution

Verified by Experts

The correct Answer is:
A
`p^2 V = "constant"`
`:. ((n R T)/V)^2 V = "constant"`
`:. T^2 prop V`
or `T prop sqrt (V)`
(V) is made three times. So, (T) will becomes `sqrt (3)` times.
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