Method 1 of Q
Temperature of two moles of a monoatomic gas is increased by 300 K in the process `p prop V`.
(a) Find molar heat capacity of the gas in the given process.
(b) Find heat given to the gas in that.

Answer

A, B

Explanation

(a) `p prop Vimplies pV^-1=` constant
If we compare with `pV^x=` constant, then
`x=-1`
Now,
`C=C_V+(R)/(1-x)`
`C_V=3/2R` for a monoatomic gas
`:.` `C=3/2R+(R)/(1-(-1))=2R`
(b) `Q=nCDeltaT`
Substituting the values, we get
`Q=(2)(2R)(300)`
`=1200R`