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Method 1 of DeltaU Temperature of two ...

Method 1 of `DeltaU`
Temperature of two moles of a monoatomic gas is increased by 600 K in a given process. Find change in internal energy of the gas.

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Verified by Experts

The correct Answer is:
A
Using the equation,
`DeltaU=nC_VDeltaT`
for change in internal energy
`C_V=3/2R` for monoatomic gas
`DeltaU=(2)(3/2R)(600)`
`=1800R`
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