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Find the ratio of (DeltaQ)/(DeltaU) and ...

Find the ratio of `(DeltaQ)/(DeltaU)` and `(DeltaQ)/(DeltaW)` in an isobaric process. The ratio of molar heat capacities `(C_p)/(C_V)=gamma`.

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The correct Answer is:
A, D
In an isobaric process `p=` constant.
Therefore, `C=C_p`.
Now, `(DeltaQ)/(DeltaU)=(nC_pDeltaT)/(nC_VDeltaT)=(C_p)/(C_V)=gamma`
and `(DeltaQ)/(DeltaW)=(DeltaQ)/(DeltaQ-DeltaU)`
`=(nC_pDeltaT)/(nC_pDeltaT-nC_VDeltaT)`
`=(C_p)/(C_p-C_V)=(C_p//C_V)/(C_p//C_V-1)`
`(gamma)/(gamma-1)`
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