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Following figure shows two process A and...

Following figure shows two process A and B for a gas. If `Delta Q_(A)` and `Delta Q_(B)` are the amount of heat absorbed by the system in two case, and `Delta U_(A)` and `Delta U_(B)` are changes in internal energies, respectively, then :

Text Solution

Verified by Experts

The correct Answer is:
A, B

`Q_1=W_1+DeltaU_1` and `Q_2=W_2+DeltaU_2`

U is a state function. Hence, `DeltaU` depends only on the initial and final position. Therefore,
`DeltaU_1=DeltaU_2`
But, `W_1 gt W_2`
as the area under 1 is greater than area under 2. Hence,
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