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A refrigerator has to transfer an averag...

A refrigerator has to transfer an average of 263J of heat per second from temperature `-10^@C` to `25^@C`. Calculate the average power consumed, assuming no enegy losses in the process.

Text Solution

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The correct Answer is:
C
Here, `T_(1)=25+273=298K`
`T_(2)=-10+273=263K`
`Q_2=263J//s`
Coefficient of performance is given by
`beta=Q_(2)/(Q_(1)-Q_(2))=T_(2)/(T_1-T_2)`
`:.` (Q_1)/(Q_2)=(T_1)/(T_2)`
`:.` `Q_1=T_1/T_2xxQ_2=298/263xx263`
`=298Js^-1`
Average power consumed,
`=298-263=35Js^-1=35W`
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