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Following figure shows two process A and...

Following figure shows two process A and B for a gas. If `Delta Q_(A)` and `Delta Q_(B)` are the amount of heat absorbed by the system in two case, and `Delta U_(A)` and `Delta U_(B)` are changes in internal energies, respectively, then :

A

(a) `DeltaQ_1=Delta_2, DeltaU_1=DeltaU_2`

B

(b) `DeltaQ_1gtDeltaQ_2,DeltaU_1gtDeltaU_2`

C

(c) `DeltaQ_1ltDeltaQ_2,DeltaU_1ltDeltaU_2`

D

(d) `DeltaQ_1gtDeltaQ_2,DeltaU_1=DeltaU_2`

Text Solution

Verified by Experts

The correct Answer is:
D
`W_1gtW_2` as area under graph-`alpha` is more. Hence,
`DeltaQ_1gtDeltaQ_2`, as
`DeltaQ=W+DeltaU` and `DeltaU_1=DetlaU_2`
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