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One mole of a monoatomic ideal gas is ta...

One mole of a monoatomic ideal gas is taken through the cycle ABCDA as shown in the figure.
`T_A=1000K` and `2p_A=3p_B=6p_C`

`[Ass um e(2/3)^0.4=0.85` and `R=(25)/(3)JK^-1mol^-1]`
Work done by the gas in the process `ArarrB` is

A

(a) 5312J

B

(b) 1875J

C

(c) 6251J

D

(d) 8854J

Text Solution

Verified by Experts

The correct Answer is:
B
In adiabatic process,
`W_(AB)=-DeltaU_(AB)`
`=nC_V(T_A-T_B)`
`=(1)(3/2R)(T_A-T_B)`
`=(1)(3/2xx25/3)(1000-850)`
`=1875J`
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