One mole of a monoatomic ideal gas is taken through the cycle ABCDA as shown in the figure. `T_A=1000K` and `2p_A=3p_B=6p_C` `[Ass um e(2/3)^0.4=0.85` and `R=(25)/(3)JK^-1mol^-1]` Heat lost by the gas in the process `BrarrC` is
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One mole of a monoatomic ideal gas is taken through the cycle ABCDA as shown in the figure. T_A=1000K and 2p_A=3p_B=6p_C [Ass um e(2/3)^0.4=0.85 and R=(25)/(3)JK^-1mol^-1] The temperature at B is
One mole of a monoatomic ideal gas is taken through the cycle ABCDA as shown in the figure. T_A=1000K and 2p_A=3p_B=6p_C [Ass um e(2/3)^0.4=0.85 and R=(25)/(3)JK^-1mol^-1] Work done by the gas in the process ArarrB is
One mole of an ideal monoatomic gas is taken through the thermodynamic process shown in the P-V diagram. The heat supplied to the system is
An ideal monoatomic gas is taken round the cycle ABCDA as shown in the P-V diagram. Compute the work done in the process.
One mole of an ideal diatomic gas is taken through a process whose P-V diagram is shown in the figure. The work done by the gas is
One mole of a monatomic ideal gas is taken through a cycle ABCDA as shown in the P-V diagram. Column II gives the characteristics involved in the cycle. Match them with each of the processes given in Column I.
One mole of a monoatomic ideal gas is taken through the cycle shown in figure. ArarrB Adiabatic expansion BrarrC Cooling at constant volume CrarrD Adiabatic compression. DrarrA Heating at constant volume The pressure and temperature at A,B etc., are denoted by p_A, T_A, p_B, T_B etc. respectively. Given, T_A=1000K , p_B=(2/3)p_A and p_C=(1/3)p_A . Calculate (a) the work done by the gas in the process ArarrB (b) the heat lost by the gas in the process BrarrC Given, (2/3)^0.4=0.85 and R=8.31J//mol-K
One mole of a monatomic ideal gas is taken through the cycle shown in the figure: A to B adiabatic expansion B to C: cooling at constant volume C to D adiabatic compression D to C: heating at constant volume. The pressure and temperature at P_A, P_B etc. T_A , T_B etc. are denoted etc. respectively. Given that T_A = 1000 K, P_B =(2 //3)P_A and P_C = (t //3)P_A Calculate the following quantities. The heat lost by the gas in process B to C (in J)
One mole of a monatomic ideal gas is taken through the cycle shown in the figure: A to B adiabatic expansion B to C: cooling at constant volume C to D adiabatic compression D to C: heating at constant volume. The pressure and temperature at P_A, P_B etc. T_A , T_B etc. are denoted etc. respectively. Given that T_A = 1000 K, P_B =(2 //3)P_A and P_C = (1 //3)P_A Calculate the following quantities. The work done by the gas in process A to B (in J)
DC PANDEY-LAWS OF THERMODYNAMICS-Level 2 Passage II
