In the circuit shown in figure potential...

In the circuit shown in figure potential differences across `6Omega` resistance is 4 volt. Find `V` and `i` values across each resistance. Also find emf `E` of the applied battery.

Text Solution

Verified by Experts

`8Omega, 2Omega` (Resultant of `6Omega` and `3Omega`) and `3Omega` (resultant of `12 Omega` and `4 Omega)` are in series. Therefore, potential drop across them should be in direct ratio of resistance. So, using this concept we can find the potential difference across other resistors. For examples, potential across `2Omega` was `4 V`. So, potential difference across `8Omega`(which is four times of `2Omega`) should be `16 V`, Similarly, potential difference across `3Omega`( which is 1.5 times of `2 Omega`) should be `16 V`. Similarly, potential difference across `3Omega`(which is 1.5 times of `2Omega`) should be 1.5 times or `6 V`.
Once` V` and `R` are knwon we can find i across that resistane. for example ltbr `i_(12Omega)=6/12=1/2A`
`i_(8Omega)=16/8=2A` etc.

Topper's Solved these Questions

CURRENT ELECTRICITY
DC PANDEY|Exercise Example Type 3|1 Videos
CURRENT ELECTRICITY
DC PANDEY|Exercise Example Type 4|1 Videos
CURRENT ELECTRICITY
DC PANDEY|Exercise Example Type 1|2 Videos
COMMUNICATION SYSTEM
DC PANDEY|Exercise Subjective|11 Videos
ELECTROMAGNETIC INDUCTION
DC PANDEY|Exercise Medical entrances gallery|25 Videos

In the given circuit diagram, potential difference across 2 Omega resistance is

`4 V`

`6 V`

`20 V`

zero

In the L-R circuit as shown in figure, potential difference across the resistance at some instant is 4 V. Then

current is increasing at a rate of 8A/s at this instant

power supplied by the battery at this instant is 20W

power stored in the magnetic field at this instant is 16W

current in the circuit at this instant is 1A

For the circuit shown in the figure what is the potential difference across the external resistance ?

10V

`7.5` V

15 V

30V