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The rated values of two bulbs are (P1, V...

The rated values of two bulbs are `(P_1, V)` and `(P_2, V)`. Find actual,power consued by both of them of they are connected in
a. series
b. Parallel
and `V` potential difference is applied cross both of them.

Text Solution

Verified by Experts

a. `:' R_1=V^2/P_1`and `R_2=V^2/P_2`
In series `P=V^2/R_("net")=V^2/(R_1+R_2)=V^2/((V^(2))/(P_(1))+(V^(2))/(P_(1)))=(P_1P_2)/(P_1+P_2)`
` or 1/P=1/P_1+1/P_2`
B in parallel `P=V^2/R_("net")=V^2(1/R_("net"))=V^2(1/R_1+1/R_2)`
`P=V^2(P_1/V^2+P_2/V^2) or P=P_1+P_2`
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