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A 100 W bulb B1, and two 60 W bulb B2 an...

A 100 W bulb `B_1`, and two 60 W bulb `B_2` and `B_3`, are connected to a 250 V source, as shown in figure. Now `W_1, W_2 and W_3` are the output powers of the bulbs `B_1, B_2 and B_3`, respectively. Then

A

`W_1 gt W_2=W_3`

B

`W_1gtW_2gtW_3`

C

`W_1 lt W_2=W_3`

D

`W_1 lt W_2 lt W_3`

Text Solution

Verified by Experts

`P=V^2/R` so, `R=V^2/P`
`:. R_1=V^2/100` and `R_2=R_3=V^2/60`
Now, `W_1=((250)^2)/((R_1+R_2)^2)R_1`
`W_2=((250)^2)/((R_1+R_2)^.R_2` and `W_2=((250)^2)/R_3`
`W_1:W_2:W_3=15:25:64 or W_1gtW_2gtW_3`
`:.` The correct option is d.
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