Find the current in each branches of the circuit.

Explanation

It is possible to use Kirchhoff's lawas in a slightly different form which may simplify the solution of certain problems. This method of applying Kirchoff's laws is called the loop current method.
In this method, we assign a current to every closed loop in a network.

Suppose currents `i_1, i_2` and `i_3` flowing in the thre loops. The clockwise or anti clockwide sence given to these currents is arbitrary. Applying Kirchoff's second law to the three loops. We get
`21-5i_1-6(i_1+i_2)-i_1=0`
`5-4i_2-6(i_1+i_2)-8(i_2+i_3)=0`
and `2-8(i_2+i_3)-16i_3=0`
Solving these three equations we get
`i_1=2A, i_2=1/2A and i_3=1/4A`
Therefore current in different brances are as shown in figure given below.