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You need produce a set of cylindrical copper wire `3.50 m` long will have a resistance of `0.125Omega` each. What will be the mass of each of these wires? Specific resistance of copper `=1.72xx10^-8Omega-m`,density of copper `=8.9xx10^3kg//m^3`

Text Solution

Verified by Experts

The correct Answer is:
A
`R=(rhol)/A`
`:. A=(rhol)/R`
`m=(Vd)`, wehre `V=` volume and d=denisty
`:. M=(A/d)`
`=rhol^2/Rd`
`((1.72xx10^-8)(3.5)^2(8.9xx0^3))/0.125`
`=15xx10^-3 kg`
`=15g`
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