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Ten cells each of emf 1 V and internal r...

Ten cells each of emf `1 V` and internal resistance `1Omega` are connected inseries. In this arrangement, polarity of two cells is reversed and the system is connected to an external resistance of `2Omega`. Find the current in the circuit.

Text Solution

Verified by Experts

The correct Answer is:
A, B
Net emf `=(n-2m)E`
`=(10-2xx2)(1)`
`=6V`
`i=("Net emf")/("Net resistance")`
`=6/(10+2)=0.5A`
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