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A micrometer has a resistance of 100 Ome...

A micrometer has a resistance of `100 Omega` and full scale deflection current of `50 muA`. How can it be made to work as an ammeter of range `5mA`?

Text Solution

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The correct Answer is:
A, B, C

`(i_(g))/(i-i_(g)) =S/G`
`:. S=((i_(g))/(i-i_(g)))G`
`=[((50xx10^-6))/((5xx10^-3-50xx10^-6))](100)~~1.0Omega`
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