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A 2.0 V potentiometer is used to determi...

A 2.0 V potentiometer is used to determine the internal resistance of `1.5 V` cell. The balance point of the cell in the circuit is `75 cm`. When a resistor of `10Omega` is connected across cel, the balance point sifts to `60 cm`. The internal resistance of the cell is

A

`1.5Omega`

B

`2.5Omega`

C

`3.5Omega`

D

`4.5Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
`r=R(l_1/l_2-1)=10(75/60-1)`
`=2.5Omega`
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