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A resistor R has power of dissipation P ...

A resistor `R` has power of dissipation `P` with cell voltage `E`. The resistor is cut in equal parts and all parts are connected in parallel with same cell. The new power dissipation is

A

`nP`

B

`nP^2`

C

`n^2P`

D

`n//P`

Text Solution

Verified by Experts

The correct Answer is:
C

`P=V^2/R` or `P prop 1/R`…..i
Resistor is cut in n equal parts. Therefoe, each resistance will become `R/n`. Now, these are connected in paralllel. Therefore, net resistance will become `1/n` times `R/n` or `R/n^2`.
Now, from Eq. i power will becomes `n^2` times.
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