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A galvanometer has a resistance of 3663O...

A galvanometer has a resistance of `3663Omega`. A shunt `S` is connected across it such that (`1//34`) of the total current passes through the galvanometer. Then the value of the shunt (in `Omega`) is

A

`222Omega`

B

`111Omega`

C

`11Omega`

D

`22Omega`

Text Solution

Verified by Experts

The correct Answer is:
111
`I_G/I_s=S/G`
`:. S=(I_G/I_S)G`
`=((1//34)/(33//34))xx3663=111Omega`
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