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Two cells A and B of emf 1.3 V and 1.5V ...

Two cells `A` and `B` of emf `1.3 V` and `1.5V `respectively are arranged as shown in figure. The voltmeter reads `1.45V`. The voltmeter is assumed to be ideal. Then

A

`r_1=2r_2`

B

`r_1=3r_2`

C

`r_2=2r_1`

D

`r_2=3r_1`

Text Solution

Verified by Experts

The correct Answer is:
B
No current will flow through voltmeter. As it is ideal (infinite resistance). Current through two batteries
`i=(1.5-1.3)/(r_1+r_2)=0.2/(r_1+r_2)`
Now, `V=E_2-ir_2`
`:. 1.45=1.5-(0.2/(r_1+r_2))(r_2)`
Solving this equation we get `r_1=3r_2`
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Knowledge Check

  • Two cells A andB ofEMF 1.3V and 1.5V respectively are arranged as shown in figure-3 .322. The voltmeter connected in circuit is ideal and it reads 1.45V. Which cell has the higher internal resistance and how many times that of the other?

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    `r_(1)=2r_(2)`
    B
    `r_(1)=3r_(2)`
    C
    `r_(2)=2r_(1)`
    D
    `r_(2)=3r_(1)`

  • In the circuit figure, the voltmeter reads 30 V. The resistance of the voltmeter is

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    `1200 Omega`
    B
    `700 Omega`
    C
    `400 Omega`
    D
    `300 Omega`

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