An ac source of emf `V=V_0 sin omegat` is connected to a capacitor of capacitance C. Deduce the expression for the current (I) flowing in it. Plot the graph of (i) `V vs. omegat`,and (ii) `I vs. omegat`

An a.c. source generating a voltage v=v+(m) sin omega t is connected to a capacitor of capacitor of capacitance C. Find the expression for the current, I, flowing through it. Plot a graph of v and I versus omega t to show that the current is pi//2 ahead of the voltage. A resistor of 200 Omega and a capacitor of 15.0 mu F are connected in series to a 220 V, 50 Hz a.c. source. Calculate the current in the circuit and the rms voltage across the resistor and the capacitor. Is the algebraic sum of these voltages more than the source voltages ? If yes, resolve the paradox.

An alternating voltage V=V_(0) sin omegat is connected to a capacitor of capacity C_(0) through an AC ammeter of zero resistance. The reading of ammeter is

A small signal voltage V(t)=V_(0)sin omegat is applied across an ideal capacitor C :

An ac source of voltage V = V_ 0sin omegat is connected to a series combination of L, C and R. Use the phasor diagram to obtain expressions for impedance of the circuit and phase with the voltage. What is circuit in this condition called?

The alternating emf of e=e_(0) sin omegat is applied across capacitor C. the current through the circuit is given by