Home
Class 12
PHYSICS
Initially the spheres A and B are at pot...

Initially the spheres A and B are at potentials `V_A` and `V_B`. Find the potential of A when sphere B is earthed.

A

`V_A`

B

`0`

C

`V_A + V_B`

D

`V_A - V_B`

Text Solution

Verified by Experts

The correct Answer is:
D

As we have studied above that the potential difference between these two spheres depends n the charge on the inner sphere only. Hence, the PD will remain unchanged because by earthing the sphere B charge on A remains constant. Let `V'A` be the new potential at A. Then
`V_A-V_B=V_A^'=V_B^'`
but `V_B^'=0` as it is earthed. Hence,
`V_A^'=V_A-V_B`
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    DC PANDEY|Exercise Example Type 8|3 Videos
  • ELECTROSTATICS

    DC PANDEY|Exercise Level 2 Single Correct|94 Videos
  • ELECTROSTATICS

    DC PANDEY|Exercise Example Type 5|5 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITORS

    DC PANDEY|Exercise (C) Chapter exercises|50 Videos
  • GRAVITATION

    DC PANDEY|Exercise All Questions|120 Videos

Similar Questions

Explore conceptually related problems

A metal sphere A of radius a is charged to potential V. What will be its potential if it is enclosed ny a spherical conducting shell B of radius b and the two are connected by a wire ?

Consider three concentric metallic spheres A, B and C of radii a, b, c respectively where a lt b lt c , A and B are connected whereas C is grounded. The potential of the middle sphere B is raised to V then the charge on the sphere C is–

A metal sphere A of radius 1m is charged to a potential of 20V .What will be its potential (in volt) when it is enclosed by a spherical conducting shell B of radius 2m and two are connected by a wire?

A metal sphere A of radius 1 m is charged to a potential of 20 V .What will be its potential (in volt) when it is enclosed by a spherical conducting shell B of radius 2 m and two are connected by a wire?

Metallic sphere of radius R is charged to potential V. Then charge q is proportional to

A conducting sphere is enclosed by a hollow conducting shell. Initially the inner sphere has a charge Q while the outer one is uncharged. The potential difference between the two spherical surface is found to be V. later on the outer shell is given a charge -4Q. The new potential difference between the two surfaces is : (A) V (B) -V (C) -2V (D) 2V