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A point charge q1 =-5.8muC is held stati...

A point charge `q_1 =-5.8muC` is held stationary at the origin. A second point charge `q_2=+4.3muC` moves from the pont `(0.26m 0,0)` to `(0.38m, 0, 0)`. How much work is doen the electric force on `q_2`?

A

`0.172 J`

B

`0.272 J`

C

`0.372 J`

D

`0.472 J`

Text Solution

Verified by Experts

The correct Answer is:
B
Work done by the electrostatic froce `=U_i-U_f`
`=(q_1q_2)/(4piepsilon_0)(1/r_i-1/r_f)`
`=(q_1q_2)/(4piepsilon_0)((r_f-r_i)/(r_i r_f))`
`=((-5.8xx10^-6)(4.3xx10^-6)(9xx10^9)(0.38-0.26))/((0.38)(0.26))`
`=0.272J`
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