Two points A and B are 2 cm apart and a uniform electric field E acts along the straight line `AB` directed A to B with `E=200N//C`. A particle of charge `+10^-6C` is taken from A to B along AB, Calculate
a. the force on the charge
b. the potential difference `V_A -V_B` and
c.the work done on the charge by E

Answer

A, B, D

Explanation

a. Electrostatic force on the charge,
`F=qE=(10^-6)(200)`
`=2xx10^-4 N`
b. In uniform electric field,
`PD. V=E.d`
or `V_A-V_B=200xx2xx10^-2`
`=4V`
c. `W(2xx10^-4)(2xx10^-2)cos0^@`
`=4xx10^-6J`