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The electrical potential function for an...

The electrical potential function for an electrical field directed parallel to the x-axis is shown in the given graph.
Draw the graph of electric field strength.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

`E=-(dV)/(dx)=-` Slope V-x graph.
From `x=-2m` to `x=0`, slope `=+5V//m`
`:. E=-5V//m`
From `x=0` to `x=2m,` slope `=0`
`:.E=0`
From `x=2m` to x=4m`, slope `=+5V//m,`
`:. E=-5V//m`
From `x=4m` to x=8m`, slope `x=--5V//m`
`:. E=+5V//m`
Corresponding E-x graph is as shown in answer.
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Knowledge Check

  • The electrical potential function for an electrical field directed parallel to the x - axis is shown in (Fig. 3.152). . The magnitude of the electric field in the x - direction in the interval 4 le x le 8 is

    A
    `2.5 NC^-1`
    B
    `5 NC^-1`
    C
    `-2.5 NC^-1`
    D
    `-5 NC^-1`
  • In the following graph , the magnitude of maximum electric field is

    A
    `5 V//m`
    B
    `2.5 V//m`
    C
    `1.25 V//m`
    D
    `10 V//m`
  • Due to an electric dipole shown in fig., the electric field intensity is parallel to dipole axis :

    A
    at P only
    B
    at Q only
    C
    both at P and at Q
    D
    neither at P nor at Q
  • DC PANDEY-ELECTROSTATICS-Level 1 Assertion And Reason
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