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Assertion: In case of charged spherical ...

Assertion: In case of charged spherical shells, E-r graph is discontinuous while V-r graph is continuous
Reason: According to Gauss's theorem only the charge inside a closed surface ca produce electric field at some point.

A

If both Assertion and Reason are true but Reason is the correct explanation of Assertion.

B

If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

C

If Assertion is true, but the Reason is false.

D

If Assertion is false but the Reason is true.

Text Solution

Verified by Experts

The correct Answer is:
C
Charge on shell does not contribute in electric field just inside the shell. But it contributes in the electric field just outside it. So there is suden change in electric field just nside and just outside it. Hence, it is discontinuous.
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(a) Use Gauss's law to show that due to a uniformly charged spherical shell of radius R, the electric field at any point situated outside the shell at a distance r from its centre is equal to the electric field at the same point, when the entire charge on the shell were concentrated at its centre. Also plot the graph showing the variation of electric field with r, for r le R and r ge R . (b) Two point charges of +1 muC and +4 muC are kept 30 cm apart. How far from the +1muC charge on the line joining the two charges, will the net electric field be zero ?

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Assertion: No net charge can exist in the region where electric field is uniform. Reason: For any type of Gaussian surface selected within the region of a uniform electric field, the angle between electric field intensity and area normal is 90^@ everywhere. Hence, electric flux linked with the selected Gaussian surface is equal to zero. If the net electric flux is zero for some Gaussian surface then according to Gauss's law the net charge enclosed within the surface must be zero.

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